如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/04 20:56:24
如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE
如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE
如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE
楼主你好
∵AB分之AE = BC分之ED = AC分之AD
∴△ABC∽△ADE,
∴∠BAC=∠DAE,
∴∠BAD=∠CAE.
满意请点击屏幕下方“选为满意回答”,谢谢.
证明:∵AB分之AE = BC分之ED = AC分之AD
∴△ABC∽△AED
∴∠BAC=∠EAD
∴∠BAC-∠DAC=∠EAD-∠DAC
即∠BAD=∠EAC
因为 AB分之AE = BC分之ED = AC分之AD
所以 三角形 ABC 与三角形ADE相似
所以 角BAC=角DAE
角BAD=角BAE-角DAE
角CAE=角BAE-角BAC
所以 角BAD=角CAE
如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE
已知:如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC.求证:ED⊥AC.
已知:如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC 求证:ED⊥AC
已知,如图,ae垂直ab,bc垂直ab,ae=ab,ed=ac 求证 ed垂直ac
已知,如图,AB⊥BC,AE⊥ED,AB=AE,
已知:如图,AB⊥BC,AE⊥ED,AB=AE,
已知:如图,AB⊥BC,AE⊥ED,AB=AE∠ACD=∠ADC.求证:BC=ED请写过程,谢谢!
已知如图,AB⊥BC,AE⊥ED,AB=AE,∠ACD=∠ADC.求证:BC=ED
蟹蟹!2.如图,已知AB⊥BC,AE⊥ED,AB=BC,∠DCE=135°,说明AE=ED
如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明:AE=ED
如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明AE=ED
如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明:AE=ED
如图,已知AB=AE,BC=ED,AC=AD,求证:BE平行CD
如图,已知AE=AD,AB=AC,求证ED⊥BC
如图,AB=AE.BC=ED.
如图,AB=AE.BC=ED.
如图,已知:AB=AE,AC=AD,AC⊥AD,AB⊥AE.求证:ED⊥BC.
如图,AE⊥AB,BC⊥AB,CD⊥ED,ED=DC.求证:AE+BC=AB.