for i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6private sub form clickfor i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6next jnext iprint xend sub 请问输出结果是多少?最好附带解释说明

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for i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6private sub form clickfor i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6next jnext iprint xend sub 请问输出结果是多少?最好附带解释说明
for i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6
private sub form clickfor i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6next jnext iprint xend sub 请问输出结果是多少?最好附带解释说明

for i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6private sub form clickfor i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6next jnext iprint xend sub 请问输出结果是多少?最好附带解释说明
在j循环时被初始化x=3,所以只有最后一次循环才决定x的值,即i=4,j=3时,k循环x+3两次,得x=9
整理一下你的代码
For i = 1 To 4
For j = 1 To 3
x = 3
For k = 1 To 2
x = x + 3
.i
X=3,所以只考虑最后外循环即i=4,j=3时,执行内循环x=3+3+3=9

private sub command_click() for i=1 to4 x=3 for j=1to3 for k=1 to 2 x=x+3 next k next j next i 输出输出str（x）解一道vb函数题,private sub command1 _click(),for i =1to4 ,for j =1to3 ,x=3 ,for k=1to 2,x=x+3,n...解一道vb函数题,private sub command1 _click(),for i =1to4 ,for j =1to3 ,x=3 ,for k=1to 2,x=x+3,next k ,next j ,next i ,text1 .text =str(x for i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6private sub form clickfor i=1to4 x=1 for j=1to3 x=3 for k=1to2 x=x+6next jnext iprint xend sub 请问输出结果是多少?最好附带解释说明假定有以下程序段 n=0 for i=1to4 for j =3 to -1 step -1 n=n+1 next j next i 运行完毕后n的值是? for(j=i+1;j 怎么用lingo求解多目标规划呢,max =@sum(I(i):@sum(J(j):@sum(link(I,J):x(i)*w(j)*p(i,j)/d(i,j))));@for(I(i):@sum(J(j)|w(j)#eq#1:x(i)*p(i,j))>0);@for(I(i):@sum(J(j):x(i)*p(i,j)*c(j))>0);@for(J(j):@sum(link(I,J):x(i)*p(i,j)>=0));@for(l for(j=1;j for(j=1;j @for(link3(i,j):c(i,j)=@if(@sum(type(l):x(l,i,j))#gt#0,1,0)); for (j=i lingo @for中大于用什么表示 @FOR(product(J)|W(J)>0:SUM(WORKER(I):X(I,J))=1); W(J)>0 要怎样表示 S←1 For i from 1to4 S←S+2^iEND FOR Print S for(i=1;i<10;i++){for(j=1;j<=i;j++)解释一下这是什么意思? main() {int i,j,w=0; for(i=4; i; i--) for(j=1;j Dim x(3,5) As Integer For i = 1 To 3 For j = 1 To 5 x(i,j) = x(i - 1,j - 1) + i + j Next j Next iprint (3,4) lingo程序求解释~n=@size(cities); min=@sum(link(i,j)|i#ne#j :distance(i,j)*x(i,j)); @sum(cities(i)|i#gt#1 :x(1,i))>=1; @for(cities(i)|i#gt#1:@sum(cities(j)|j#ne#i:x(j,i))=1; @for(cities(j)|j#gt#1#and#j#ne#i:level(j)>=level(i)+x(i,j)-(n-2)*(1-x(i, 没有循环体的for语句结果是什么.for(i=3;i>=1;i--);{ for(j=1;j for(j=1;j<=n;j++) { for(i=1;i<m;i++) 数据结构,怎么循环