|x-3|+|2y-8|+|z-2|=0 求x-3y-z的值
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|x-3|+|2y-8|+|z-2|=0 求x-3y-z的值
|x-3|+|2y-8|+|z-2|=0 求x-3y-z的值
|x-3|+|2y-8|+|z-2|=0 求x-3y-z的值
|x-3|+|2y-8|+|z-2|=0
则x-3=0,2y-8=0,z-2=0,得
x=3,y=4,z=2
x-3y-z
=3-3×4-2
=3-12-2
=-11
3-12-2=??
绝对值≥0 所以 x-3=0 2y-8=0 z-2=0 x=3 y=4 z=2
x-3y-z=3-3×4-2=-11
-11
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