等比数列{an}中,a1*a3*a11=8,求a2*a8

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等比数列{an}中,a1*a3*a11=8,求a2*a8
等比数列{an}中,a1*a3*a11=8,求a2*a8

等比数列{an}中,a1*a3*a11=8,求a2*a8
a1*a3*a11=a1*(a1*q^2)*(a1*q^10)
=a1^3*q^12=8
所以a1*q^4=2
a2*a8=(a1*q)*(a1*q^7)
=a1^2*q^8
=4

a1*a3*a11=a1*a1*q^2*a1*q^10=a1^3*q^12=(a1*q^4)^3=a5^3=8
故a5=2
所以a2*a8=a5^2=2^2=4
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等比数列中有个重要推论:
m+n =x+y (m,n,x,y不为0)
am *an = ax *ay
所以:
a1*a3*a11 = a2*a8*a5 = (a5)^ 3=8
a2*a8 = 4