已知实数x,y满足 根号x-2 + (y+1)²=0,则x-y等于
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已知实数x,y满足 根号x-2 + (y+1)²=0,则x-y等于
已知实数x,y满足 根号x-2 + (y+1)²=0,则x-y等于
已知实数x,y满足 根号x-2 + (y+1)²=0,则x-y等于
√x-2 + (y+1)²=0
则x-2=0 y+1=0
x=2 y=-1 x-y=3
根号x-2 + (y+1)²=0
则 x-2=0, x=2
y+1=0, y=-1
x+y=1
√[x-2+(y+1)²]=0,则:x-2=0①,y+1=0②。①-②得:x-2-(y+1)=0,则:x-y=3。
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