等差数列an中,a11=4,求s21

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等差数列an中,a11=4,求s21
等差数列an中,a11=4,求s21

等差数列an中,a11=4,求s21
a11=a1+10d=4
a21=a1+20d
s21=(a1+a21)*21/2=(a1+a1+20d)*21/2=8*21/2=84

S21=21a1+21(21-1)d/2=21a1+210d=21(a1+10d)=21a11=84

a1+a21=2a11=8
S21=(a1+a21)*21/2=8*21/2=84

等差数列有个很重要的性质
a1+a21=2a11=8
S21=(a1+a21)*21/2=8*21/2=84