设数列an满足a0=0 an+1=can^3

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设数列an满足a0=0 an+1=can^3
设数列an满足a0=0 an+1=can^3

设数列an满足a0=0 an+1=can^3
由归纳法可知,a(n)=0.
证明如下:
n=0时,有a(0)=0,
设n=k时,a(k)=0.
则n=k+1时,
a(k+1)=c*[a(k)]^3=c*0=0.
因此,
总有a(n)=0,n=0,1,2,...

a(n+1)=can^3
a1=ca0^3=0
an=0

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