计算3x[xy-2x(1/y-x/3]+3y(x²-y²)
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计算3x[xy-2x(1/y-x/3]+3y(x²-y²)
计算3x[xy-2x(1/y-x/3]+3y(x²-y²)
计算3x[xy-2x(1/y-x/3]+3y(x²-y²)
原式=3x(xy-2x/y+2x²/3)+3x²y-3y³
=3x²y-6x²/y+2x³+3x²y-3y³
=2x³+6x²y-3y³-6x²/y
3x[xy-2x(1/y-x/3]+3y(x²-y²)
=3x²y -6x²/y+x²+3x²y-3y3
=6x²y-6x²/y+x²-3y3
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