已知x^2-6xy+y^2+10y+34=0求x和y的值
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已知x^2-6xy+y^2+10y+34=0求x和y的值
已知x^2-6xy+y^2+10y+34=0求x和y的值
已知x^2-6xy+y^2+10y+34=0求x和y的值
-6xy是-6x
则(x²-6x+9)+(y²+10y+25)=0
(x-3)²+(y+5)²=0
所以x-3=y+5=0
x=3,y=-5
x^2-6x+y^2+10y+34=0
x^2-6x+9+y^2+10y+25=0
(x-3)^2+(y+5)^2=0
由非负性
x-3=0 y+5=0
解得
x=3 y=-5
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