x/20=(x-32-32)/12
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x/20=(x-32-32)/12
x/20=(x-32-32)/12
x/20=(x-32-32)/12
12X=20(X-64)
12X=20X-20*64
12X=20X-1280
-8X=-1280
8X=1280
X=1280/8
X=160
12X=20(X-64)
12X=20X-1280
8X=1280
X=160
`12X=20(X-64)
12X=20X-1280
-8X=-1280
X=160
matlab中a=[x(11)/x,x(12)/x;x(21)/x,x(22)/x;x(31)/x,x(32)/x;x(41)/x,x(42)/x;x(51)/x,x(52)/x]咋错了
x/20=(x-32-32)/12
X-20%X=32
(30-x):(18+x)=(20+x):(32-x)
x-2=(104-x)+2 6x-59=10x-75 (x+10)+(x-15)=280-x4(x-62)=x-38 60x-40=(60+20)*(x-5) 32x+32*0.5-25x+64x=24x+496-49x x+15=3*(109-x ) 5(3x-1.4)=2(6x-0.5) 3(x+0.9)=5(x-1.7) 13x-4(2x+5)=17(x-2)-4(2x-1) (13x+8)/3=5x-1x-60=2[(3561-x)+100]+1 (x+9)+12=2[(x-9)-1
(16x-13)/(4x-3)-(20x-24)/(4x-5)=(32x-30)/(8x-7)-(40x-43)/(8x-9)求x
(x-20)*3=x+32 求x
X÷48%=X+(X+32)
16x+32=12x-2
3x+2(12-x)=32
(20-X)(32-2X)=540
2x平方+32=20x
x-20%x=32分之9
(32-2x)*(20+x)=570
2X^2+3X=27 X=?5x^3-3x^2-32x-12 因式分解
解下列方程!就三道!都来看看吧!急死我了!1、x/(x-2) - (1-x²)/x²-5x = 2x/x-32、5x/(x²+x-6) - (5-2x)/x²-x-12=7x-10/x²-6x+83、x-4/(x-5) + (x-8)/x-9=x-7/(x-8) + (x-5)/x-6
5x+2x=33.6,7x-4x=0.75,2x+7x+2.1=12,56x-32x-119=361,解方程
18%x+32%x=2 x+20%x=2.4 x+5%x=4.2 15%x+35%x=0.2