计算log(x) 8=–2/12345.求X的值
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计算log(x) 8=–2/12345.求X的值
计算log(x) 8=–2/12345.求X的值
计算log(x) 8=–2/12345.求X的值
根据题意:-12345*log(x) 8/2=1
即:log(x)( 8^(-12345/2))=1
所以:x=8^(-12345/2)=8^(-6172.5)
x^(-2/12345)=8 x=8^(2/12345)
snmgdbm
计算log(x) 8=–2/12345.求X的值
log(x+5)=log(x)+log(2) log(8)+log(x)=log(24) 2log(x)=log(2x)+log(3)
简化2log (x + 4) – log(2x + 8) + log(x - 2)谢谢~
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