因式分解,（1）（x^2+1)y^2-x^2-1 (2)a-ab^2 (3)2a^4+4a^3+2a^2 (4)a^2(a-1)-4(1-a)^2

因式分解,（1）（x^2+1)y^2-x^2-1 (2)a-ab^2 (3)2a^4+4a^3+2a^2 (4)a^2(a-1)-4(1-a)^2
因式分解,（1）（x^2+1)y^2-x^2-1 (2)a-ab^2 (3)2a^4+4a^3+2a^2 (4)a^2(a-1)-4(1-a)^2

因式分解,（1）（x^2+1)y^2-x^2-1 (2)a-ab^2 (3)2a^4+4a^3+2a^2 (4)a^2(a-1)-4(1-a)^2
还是不要回答的好,一看就猜到是小朋友懒得做作业上来找答案的,道德问题啊

（1）（x^2+1)y^2-x^2-1
=(x²+1)(y²-1)
=(x²+1)(y+1)(y-1)
(2)a-ab^2
=a(1-b²)
=a(1+b)(1-b)
(3)2a^4+4a^3+2a^2
=2a²(a²+2a+1)
=2a²(a+1)²
(4)a^2(a-1)-4(1-a)^2
=(a-1)(a²-4a+4)
=(a-1)(a-2)²

（1）（x^2+1)y^2-x^2-1
=x²y²+y²-x²-1
=x²y²-1
=(xy-1)(xy+1）
(2)a-ab^2
=a（1-b²）
=a(1-b)(1+b)
(3)2a^4+4a^3+2a^2
=2a²（a²+2a+1）
=2a²（a+1）²
(4)a^2(a-1)-4(1-a)^2
=(a-1)(a²-4a+4)
=(a-1)(a-2)²

1）（x^2+1)y^2-x^2-1
=(x²+1)(y+1)(y-1)
(2)a-ab^2
=a(1-b²)
=a(1+b)(1-b)
(3)2a^4+4a^3+2a^2
=2a²(a²+2a+1)
=2a²(a+1)²
(4)a^2(a-1)-4(1-a)^2
=(a-1)(a²-4a+4)
=(a-1)(a-2)²

(1)（x^2+1)y^2-x^2-1
=x^2y^2+y^2-x^2-1
=x^2(y^2-1)+y^2-1
=(x^2+1)(y^2-1)
=(x^2+1)(y-1)(y+1)
(2)a(1-b)(1+b)
(3)2a^4+4a^3+2a^2
=2a^4+2a^3+2a^3+2a^2
=2a^3(a+1)+2a^2(a+1)
=(2a^3+2a^2)(a+1)
=2a^2(a+1)^2
(4)a^2(a-1)-4(1-a)^2
=(a-1)(a^2-4a+4)
=(a-1)(a-2)^2