$sql = "select tb_note.*,answ.* from tb_note left join";这句话解释下,left 还有.*,answ.*

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$sql = "select tb_note.*,answ.* from tb_note left join";这句话解释下,left 还有.*,answ.*
$sql = "select tb_note.*,answ.* from tb_note left join";这句话解释下,
left 还有.*,answ.*

$sql = "select tb_note.*,answ.* from tb_note left join";这句话解释下,left 还有.*,answ.*
这是一个sql,而且是没写完成的sql
正确的应该是:
select tb_note.*,answ.* from tb_note left join answ on 条件
tb_note.*表示选择tb_note表的全部字段
answ.*表示选择answ表的全部字段
left join是左连接,把2个表连接起来

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