sin(x*x+y)=xy 求y'x
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sin(x*x+y)=xy 求y'x
sin(x*x+y)=xy 求y'x
sin(x*x+y)=xy 求y'x
y'x是对y求关于x的导数吧?
两边求导:
cos(x*x+y)*(2*x+y')=y+xy'
所以
y'=(2*x*cos(x*x+y)-y)/(x-cos(x*x+y))
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