作业帮how_many_legs should take a string which is the name of an animal and return a number representing how many legs the animal has.It needs to recognise at least the following animals:human,chicken,horse,dog,spider,centipede.If it is given an animal it
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how_many_legs should take a string which is the name of an animal and return a number representing how many legs the animal has.It needs to recognise at least the following animals:human,chicken,horse,dog,spider,centipede.If it is given an animal it
how_many_legs should take a string which is the name of an animal and return a number representing how many legs the animal has.It needs to recognise at least the following animals:human,chicken,horse,dog,spider,centipede.If it is given an animal it does not recognise,it should print an error message and then return 0.
自己做的：
def how_many_legs(name):
if name == "horse" or "dog":
return "this animal have 4 legs"
if name == "chicken" or "human":
return "this animal have 2 legs"
if name == "spider":
return "this animal have 8 legs"
if name == "centipede":
return "this animal have 30 or 34 legs"
else:
return "error,0"
它就只会打"this animal have 4 legs",求更正,
how_many_legs should take a string which is the name of an animal and return a number representing how many legs the animal has.It needs to recognise at least the following animals:human,chicken,horse,dog,spider,centipede.If it is given an animal it
def how_many_legs(name):
if name == "horse" or name =="dog":
return "this animal have 4 legs"
if name == "chicken" or name =="human":
return "this animal have 2 legs"
if name == "spider":
return "this animal have 8 legs"
if name == "centipede":
return "this animal have 30 or 34 legs"
else:
return "error,0"