(x2y)3 × (-xy2)3
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/07 18:35:33
(x2y)3 × (-xy2)3
(x2y)3 × (-xy2)3
(x2y)3 × (-xy2)3
(x2y)3 × (-xy2)3
=-x^9y^9
3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]
(x2y)3 × (-xy2)3
5xy2-【3xy2-(4xy2-2x2y)】+2x2y】+2x2y-xy2 化简,再求值
化简:5(3x2y-xy2) * (xy2+3x2y)
-3x2y+2x2y+3xy2-2xy2
-3x2+2x2y+xy2
-2x2y(-2xy2)2+(2xy)3×( xy2)
化简 5(3x2y-xy2)- (xy2+3x2y)怎么算啊
(6x2y-xy2-1/2x2y3)/(-3xy)
(-1/2x2y)`(-3xy2)=
4xy2-4x2y-y3 (2 3 是方)
(3x2y-2xy2)-(xy2-2x2y),其中x=-1,y=2.
若m=x3-3x2y+2xy2+3y2 n=x3-2x2y+xy2-5y3,则2x3-7x2y+5xy2+14y2等于( )若m=x3-3x2y+2xy2+3y2 n=x3-2x2y+xy2-5y3,则2x3-7x2y+5xy2+14y2等于( )空里用字母表示
x.y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3).y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3)的值都是常数?
一个多项式加上+x2y-3xy2得x的3次方-3x2y,这个多项式是
计算:3xy(x2y-xy2+xy)-xy2(2x2-3xy+2x)因式分解
试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
已知:(x+2)2+|y+1|=0,求5xy2-{2x2y-[3xy2-(4xy2-2x2y)]}的值