已知4a2+b2-4a-6b+10=0,求(2/3a√9a+b2√a/b3)-(a2√1/a-5a√b/a)如题,

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已知4a2+b2-4a-6b+10=0,求(2/3a√9a+b2√a/b3)-(a2√1/a-5a√b/a)如题,
已知4a2+b2-4a-6b+10=0,求(2/3a√9a+b2√a/b3)-(a2√1/a-5a√b/a)
如题,

已知4a2+b2-4a-6b+10=0,求(2/3a√9a+b2√a/b3)-(a2√1/a-5a√b/a)如题,
4a2+b2-4a-6b+10=0
4a²-4a+1+b²-6b+9=0
(2a-1)²+(b-3)²=0
∴2a-1=0
b-3=0
∴a=1/2
b=3

(2/3a√9a+b2√a/b3)-(a2√1/a-5a√b/a)
=2√a+√ab-√a+5√ab
=√a+6√ab
=√(1/2)+6√(3/2)
=√2/2+3√6