作业帮∫（COS2X）／（1十SinXCOSX）dX＝
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 02:12:04
∫（COS2X）／（1十SinXCOSX）dX＝
∫（COS2X）／（1十SinXCOSX）dX＝
∫（COS2X）／（1十SinXCOSX）dX＝
∫（COS2X）／（1十SinXCOSX）dX
=∫(1/2)/(1+sin2x/2)d(sin2x)
=∫(1/2)/(1+u/2)du(u=sin2x)
=∫1/(u+2)d(u+2)
=ln|u+2|+C
=ln|sin2x+2|+C
=ln(sin2x+2)+C
∫（COS2X）／（1十SinXCOSX）dX＝
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