1 (a-b)(3a+b)²+(a+3b)²(b-a)2 (2x²+1)²-4(x²+2x)²3 (a+b)²-2(a²-b²)+(a-b)²4 a²-2ab+b²-a+b

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1 (a-b)(3a+b)²+(a+3b)²(b-a)2 (2x²+1)²-4(x²+2x)²3 (a+b)²-2(a²-b²)+(a-b)²4 a²-2ab+b²-a+b
1 (a-b)(3a+b)²+(a+3b)²(b-a)
2 (2x²+1)²-4(x²+2x)²
3 (a+b)²-2(a²-b²)+(a-b)²
4 a²-2ab+b²-a+b

1 (a-b)(3a+b)²+(a+3b)²(b-a)2 (2x²+1)²-4(x²+2x)²3 (a+b)²-2(a²-b²)+(a-b)²4 a²-2ab+b²-a+b
1.原式=(a-b)(3a+b)²-(a+3b)²(a-b)
=(a-b)[(3a+b)²-(a+3b)²]
=(a-b)(3a+b+a+3b)(3a+b-a-3b)
=(a-b)(4a+ab)(2a-2b)
=8(a+b)(a-b)²
2.原式=[2x²+1+2(x²+2x)][2x²+1-2(x²+2x)]
=(4x²+4x+1)(1-4x)
=(2x+1)²(1-4x)
3.原式=(a+b)²-2(a-b)(a+b)+(a-b)²
=[a+b-(a-b)]²
=4b²
4.原式=(a-b)²-(a-b)
=(a-b)(a-b-1)

1 (a-b)(3a+b)²+(a+3b)²(b-a)
=(3a+b)²(a-b+b-a)
=0
2 (2x²+1)²-4(x²+2x)²
[2x²+1+2(x²+2x)][2x²+1-2(x²+2x)]
=(4x²+4x+1)(...

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1 (a-b)(3a+b)²+(a+3b)²(b-a)
=(3a+b)²(a-b+b-a)
=0
2 (2x²+1)²-4(x²+2x)²
[2x²+1+2(x²+2x)][2x²+1-2(x²+2x)]
=(4x²+4x+1)(1-4x)
=(2x+1)²(1-4x)
3 (a+b)²-2(a²-b²)+(a-b)²
=(a+b)²-2(a-b)(a+b)+(a-b)²
=[a+b-(a-b)]²
=4b²
4 a²-2ab+b²-a+b
=(a-b)²-(a-b)
=(a-b)(a-b-1)

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分解因式 (a²+b²-1)²-4a²b² 1 (a-b)(3a+b)²+(a+3b)²(b-a)2 (2x²+1)²-4(x²+2x)²3 (a+b)²-2(a²-b²)+(a-b)²4 a²-2ab+b²-a+b [(a+b)²/(a-b)²] X (2a-2b)/(3a+3b) - a²/(a²-b²)X b/a 的值如题 计算:3a³b²÷a²+b*(a²b-3ab-5a²b) a=-1/2,b=1/4,求(8a²-2b²)÷(4a²b+4ab²+b²/2b²-5ab-3aa=-1/2,b=1/4,求(8a²-2b²)÷(4a²b+4ab²+b²/2b²-5ab-3a²)×(ab²/b²-5ab+6a²)大哥大姐们, 若2a²+3a+b=4,求{(a+b)(a-b)+(a-b)²+4a²(a+1)}/a的值 两道代数题{急}1、化简求值:当a:b=3:1时,求a/a-b+(b/a+b)+(b²/a²b²)的值.2、若a、b、c是△ABC的三边长,且满足a²c²-b²c²=(a²-b²)²,判定这个三角形的形状. a²+b²+2/2和a²-2b²+1/3比较大小是(a²+b²+2)/2和(a²-2b²+1)/3嘿嘿、不好意思 …… 2(a-b)²(a+b)-(b-a)²(3a-b)因式分解 (a+b/a-b)²×(2a-2b/3a+3b)-(a²/a²-b²)÷(a/b) (a+b/a-b)² * 2a-2b/3a+3b - a²/a²-b² ÷ a/b ab(a+b)² -(a+b)-1a²+ab-2b²x²-4xy+4y²-3x+3y+2 已知|a-3|+(b+1)²=0,求5ab²-[2a²b-(4ab²-2a²b)]的值. 已知|a-3|+(b+1)²=0,求5ab²-[2a²b-(4ab²-2a²b)]的值. 会的请进!若a+b=1,求证:a/(b²-1) - b/(a³-1) = 2(b-a)/(a²b²+3) (1)ab²分之c+ab²分之bc=?(2) (a-b)²分之a²-(b-a)²分之b²=?(3)4a²分之b²-a分之c=?(4)a-b分之a-b分之b=?(5)a+b分之b+b²-a²分之ab=?(6)a-b+ a+b分之2b²=?有 2010×2012-2011² 2011²-2012×2010 已知a+b=3,a×b=-12,a²b²= ,a²-ab+b&sup已知a+b=3,a×b=-12,a²b²= ,a²+b²= ,a²-ab+b²= (a-b)²= 算式:3(a³-a²b+1/2ab²)-1/2(6a²+4a²b+3ab²)