若m^2-2m+10=6n-n^2,求[m^2-n^2/m^2+2mn+n^2+2/mn/(1/m+1/m)^2/1/m+n的值,答案是-1/2,
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 16:51:53
若m^2-2m+10=6n-n^2,求[m^2-n^2/m^2+2mn+n^2+2/mn/(1/m+1/m)^2/1/m+n的值,答案是-1/2,
若m^2-2m+10=6n-n^2,求[m^2-n^2/m^2+2mn+n^2+2/mn/(1/m+1/m)^2/1/m+n的值,答案是-1/2,
若m^2-2m+10=6n-n^2,求[m^2-n^2/m^2+2mn+n^2+2/mn/(1/m+1/m)^2/1/m+n的值,答案是-1/2,
m^2-2m+10=6n-n^2
m^2-2m+1=-9+6n-n^2
(m-1)²=-(n-3)²
所以m-1=n-3=0
所以m=1 n=3
先化简再代入求值即可
若m平方+n平方+2m-6n-6n+10=0求m n的值.
已知m^2+n^2-6m+10n+34=0,求m-n
m^2+n^2-6m+10n+34=0,求m+n
m^2+n^2-6m+10n+34=0求m+n的值
m*+n*+2m-6n+10=0 ,求m+n?
若4m^2+n^2-6n+4m+10=0,求m^-n的值
若m-n=3,3m+2n=2,求代数式6m(m-n)-4n(n-m)的值
若(m^2)-2m+10=6n-(n^2),求{(m^2-n^2)/(m^2+2mn+n^2)+(2/mn)÷(1/m+1/n)^2}÷[1/(m+n)]的值
m/n=5/3,求(m/m+n)+(m/m+n)-(n^2/m^2-n^2)
若m-2m+10=6n-n 求【m-n/m+2mn+n+2/mn÷(1/m+1/n)】÷1/m+n 怎样做?
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
若2M=2N 求分式(1+m/n-n/n-m)除以(1-(m/n)-n/n+m)
若2M=2N 求分式(1+m/n-n/n-m)除以(1-(m/n)-n/n+m)
若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值
若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值
若2m-n/m+2n=5,求3(2m-n)/m+2n-m+2n/2m-n+3的值
若2m-n/m+2n=5,求3(2m-n)/m+2n-m+2n/2m-n+3的值
若M*M-N*N=MN,求M*M/N*N+N*N/M*M (2)123*123-124*124