作业帮AP物理题,英语学霸快来,
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AP物理题,英语学霸快来,
AP物理题,英语学霸快来,
AP物理题,英语学霸快来,
19 假设正方向为west,有
30-（-45）=75 km/h
故改变量为 75km/h,方向为west
20 v=sqrt(11^2+5^2)=12.0 m/s
θ=arctan(11/5)=65.6°
方向为北偏东65.6°.
21 vx= -185+85cos(45°)= -124.90
vy=85sin(45°)=60.10
v=sqrt(vx^2+vy^2)=138.61 m/s
θ=arctan(124.9/60.1)=64.3°
方向为北偏西64.3°
22 θ=arcsin(170/2700)=3.61°
s=h/sinθ=45/sin3.61°=714.70 m
23 建筑物高度 h=49-14 =35 ft
船到建筑物的水平距离 width=h/tanθ=35/tan30°=60.6 ft
船到岩石的距离 60.6-19=41.6 ft
选c ┏ (^ω^)=
楼主你这像素实在是。。。。我先下载图片，慢慢做
19. Suppose west to be the positive direction, ΔV=V2-V1=（30-（-45））=75kM/h, therefore the magnitude of the change velocity will be 75kM/h, and the direction will be West.哈哈，...
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楼主你这像素实在是。。。。我先下载图片，慢慢做
19. Suppose west to be the positive direction, ΔV=V2-V1=（30-（-45））=75kM/h, therefore the magnitude of the change velocity will be 75kM/h, and the direction will be West.
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