先化简.再求值:(3a^2-ab)/(9a^2-6ab+b^2),其中a=3/4,b=-2/3谢谢啊,各位,帮帮忙

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先化简.再求值:(3a^2-ab)/(9a^2-6ab+b^2),其中a=3/4,b=-2/3谢谢啊,各位,帮帮忙
先化简.再求值:(3a^2-ab)/(9a^2-6ab+b^2),其中a=3/4,b=-2/3
谢谢啊,各位,帮帮忙

先化简.再求值:(3a^2-ab)/(9a^2-6ab+b^2),其中a=3/4,b=-2/3谢谢啊,各位,帮帮忙
原式=a(3a-b)/(3a-b)ˆ2
=a/3a-b
因为a=3/4,b=-2/3
所以原式=9/35

原式=a(3a-b)/(3a-b)²
=a/(3a-b)
=(3/4)/(3×3/4+2/3)
=9/35

(3a^2-ab)/(9a^2-6ab+b^2)=a(3a-b)/(3a-b)^2=a/(3a-b),代入a=3/4,b=-2/3,得9/35

(3a^2-ab)/(9a^2-6ab+b^2
=[a(3a-b)]/[(3a-b)^2]
=a/(3a-b) 因为3a-b不为0
∵a=3/4,b=-2/3
∴带入上式得9/35