已知sin( π/2+ θ )=3/5则cos( π -2 θ )等于
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已知sin( π/2+ θ )=3/5则cos( π -2 θ )等于
已知sin( π/2+ θ )=3/5则cos( π -2 θ )等于
已知sin( π/2+ θ )=3/5则cos( π -2 θ )等于
解
sin( π/2+ θ )=-cosθ=3/5
则cosθ=3/5
cos( π -2 θ )
=-cos2 θ
=-(2cos²θ-1)
=-(2*9/25-1)
=-(-7/25
=7/25
由题意 sin( π/2+ θ )=cosθ =3/5
∴cos( π -2 θ )=-cos2θ =-(2cosθ的平方-1)=7/25
sin(π/2+θ)=cosθ=3/5
cosθ=3/5
(cosθ)^2=9/25
(sinθ)^2=16/25
cos2θ=(cosθ)^2-(sinθ)^2=-7/25
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