-π/3 ∫(sin x+cos x)dx=? -π/4
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 10:08:34
-π/3 ∫(sin x+cos x)dx=? -π/4
-π/3 ∫(sin x+cos x)dx=? -π/4
-π/3 ∫(sin x+cos x)dx=? -π/4
原式=--π/3 (-cosx+sinx)
求不定积分∫cos x/(sin x+cos x) d x,
如果f(cos x)=sin 3x,那么f(sin x)等于A.sin 3x B.-sin 3x Ccos 3x D-cos 3x
d/dx sin^8(cos(4x))
化简sin(x)(cos(x)+cos(3x)+cos(5x)+cos(7x))
使用微积分基本原理 (1)∫(x sin√(x^2+4))/√(x^2+4) dx(2)∫x^2 sin(x^3+5) cos^9 (x^3+5)dx(3)∫_0^(π/2)sinxsin(cosx)dx(4)∫_(-π/2)^(π/2)cosθ cos(π sinθ)dθ
已知sin(x)+3cos(x)=2,求sin(x)-cos(x)/sin(x)+cos(x)=?
cos(x+π/3)是不是等于sin(x-π/6)
cos(π/6-x)=sin(π/3+x)?为什么
求不定积分:∫(sin x/cos^3 x)dx
∫(cos^3x/sin^2x)dx
求不定积分:∫(sin x/cos^3 x)dx
∫cos^4x/sin^3x dx=?
∫sin(3x)cos(4x)dx=
∫ [cos^3(x)]/[sin^2 (x)]dx
∫sin^3(x)cos^2(x)dx=
求积分:∫sin^2 (x) /cos^3 (x) dx
∫ sin^4(x)cos^3(x)dx
∫sin(x) cos^2(x)dx