求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移)of the particle from t=0 to t=4.
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求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移)of the particle from t=0 to t=4.
求一道英文数学题的答案
If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18
Find the distance(距离非位移)of the particle from t=0 to t=4.
求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移)of the particle from t=0 to t=4.
对x(t)求导,得到6t^2-18t+12,令这个式子等于0,则有x=1或者2,即x(t)在这两点处取得极值;再根据单调性大致得出波形,
x(0)= -18;x(1)= -13;x(2)= -14;x(4)= 14;
由波形知距离=|x(1) - x(0)| + |x (2) - x(1)| + |x(4) - x(2)| =34
(方法肯定是对的,结果你自己再算下,应该没有错)
求两点(0,-18),(4,14)间距离,结果是4*65½,四倍的六十五开平方
x(t)=2t^3-9t^2+12t-18
x(0)=-18
x(4)=2*4^3-9*4^2+12*4-18=14
x(4)-x(0)=32