(3x^n)^3除以(2x^n)^2乘(6x^2)^2=
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(3x^n)^3除以(2x^n)^2乘(6x^2)^2=
(3x^n)^3除以(2x^n)^2乘(6x^2)^2=
(3x^n)^3除以(2x^n)^2乘(6x^2)^2=
(3x^n)^3除以(2x^n)^2乘(6x^2)^2
=27x^(3n)除以(4x^(2n))乘(36x^4)
=27x^n除以4乘(36x^4)
=27*9*x^(n+4)
=243x^(n+4)
(3x^n)^3除以(2x^n)^2乘(6x^2)^2
=27x^3n÷(4x^2n)×36x^4
=27×36/4×x^(3n-2n+4)
=243x^(n+4)
解;﹙3x^n﹚³÷﹙2x^n﹚²×﹙6x²﹚²
=27x^3n÷﹙4x^2n﹚×36x^4
=243x^﹙n+4﹚.
你题目的分子分母有歧义,(6x^2)^2到底是分子还是分母呢,
如果(6x^2)^2是分子,
= (27 * x^(3 * n)) * (36 * x^4) / (4 * x^(2 * n))
= 27 * 36 * x^(3 * n + 4) / (4 * x^(2 * n))
= 27 * 9 * x^(3 * n + 4) / x^(2 * n)
= ...
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你题目的分子分母有歧义,(6x^2)^2到底是分子还是分母呢,
如果(6x^2)^2是分子,
= (27 * x^(3 * n)) * (36 * x^4) / (4 * x^(2 * n))
= 27 * 36 * x^(3 * n + 4) / (4 * x^(2 * n))
= 27 * 9 * x^(3 * n + 4) / x^(2 * n)
= 27 * 9 * x^(3 * n + 4 - 2 * n)
= 263 * x^(n + 4)
如果(6x^2)^2是分母,
= (27 * x^(3 * n)) / (4 * x^(2 * n)) * (36 * x^4)
= (27 * x^(3 * n)) /( 4 * 36 * x^(2 * n + 4))
= (3 / 16) * x^(3 * n -2 * n - 4)
=(3 / 16) * x^(n - 4)
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