sin(5π/12)-√3cos(5π/12)=
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sin(5π/12)-√3cos(5π/12)=
sin(5π/12)-√3cos(5π/12)=
sin(5π/12)-√3cos(5π/12)=
sin(5π/12)-√3cos(5π/12)
=2sin(5π/12-π/3)
=2sin(π/12)
=2sin(π/3-π/4)
=2[sin(π/3)cos(π/4)-cos(π/3)sin(π/4)]
=2[(√3/2)*(√2/2)-(1/2)*(√2/2)]
=(√6-√2)/2
-sin(π/12)
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sin(5π/12)-√3cos(5π/12)=
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