已知sin(a+P)=1,求证tan(2a+P)+tanP=0
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已知sin(a+P)=1,求证tan(2a+P)+tanP=0
已知sin(a+P)=1,求证tan(2a+P)+tanP=0
已知sin(a+P)=1,求证tan(2a+P)+tanP=0
sin(a+P)=1 a+p=1/2π+2kπ k属于整数
tan(2a+p)=tan[2(a+p)-p]=tan(π-p)=tan(-p)=-tanp
所以tan(2a+p)+tanp=0 望采纳
已知sin(a+P)=1,求证tan(2a+P)+tanP=0
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