求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/02 18:33:00
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
只有类似例题、
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8!急救急救
sin(a-π)+5cos(2π-a)+4cos(π+a)/cos(π-a)-sin(-a) 求
sin(α-π)=2cos(α-2π)求cos平方α-sin平方αcosα
sin@-2cos@=0 a属于π/2求sin@ cos@的值
已知0<α<π/2,且3sinα=4cosα求(sin^2α+2sinαcosα)/(3cos^2α-1)求cos^2α+sinαcosα
cosπ/4cosθ-sin3π/4sinθ=0,求θ
已知sin(3π+α)=2cos(α-4π)求cos(π/2 -α)+5sin(π/2 +α)/2cos(π+α)-sin(-α)
【三角函数】已知sin(α-π)=2cos(2π-α),求[sin(π-α)+5cos(2π-α)]/[3cos(π-α)-sin(-α)]
已知sin(a-π)=2cos(2π-a),求(sin(π-a)+5cos(2π-a))/(3cos(π-a)-sin(-a))的值.
sin(a-π)=2cos(2π-a).求3cos(π-a)-sin(-a)/sin(π-a)+5cos(2π-a)
若sin(π-a)=2cos(2π-a),求sin(π-a)+5cos(2π-a)/3cos(π-a)-sin(-a)的值
已知sin(a-π)=2cos(2π-a),求sin(π-a)+5cos(2π-a)/3cos(π-a)+sin(-a)的值.
设0≤x≤π/2,求cos(sinx)>sin(cos)
已知tan(θ+π/4)=-2,求cosθ平方+sinθcosθ-1
已知√3sinα+cosα=2/3,求cos(2α-π/3)
tan(π/4+α)=2,求1/(2cosαsinα+cos^2α)
求sinπ/8cosπ/8的值