已知x²-4x+4+|y+3|=0,求代数式（x-1/2-1）（x-1/2+1）-(x-1/2y-1)²的值

已知x²-4x+4+|y+3|=0,求代数式（x-1/2-1）（x-1/2+1）-(x-1/2y-1)²的值
已知x²-4x+4+|y+3|=0,求代数式（x-1/2-1）（x-1/2+1）-(x-1/2y-1)²的值

已知x²-4x+4+|y+3|=0,求代数式（x-1/2-1）（x-1/2+1）-(x-1/2y-1)²的值

x²-4x+4等于0，|y+3|等于0，则x为2，y为-3，后面代数式看不懂~~~~“-”是什么意思

x²-4x+4+|y+3|=0
(x-2)²+|y+3|=0
∴x-2=0；y+3=0
即：x=2；y=-3
（x-1/2-1）（x-1/2+1）-(x-1/2y-1)²
=（x-1/2)²-1-(x-y/2-1)²
=(2-1/2)²-1-(2+3/2-1)²
=9/4-1-25/4
=-5