(4+3x^3-7x^2)÷(2+3x)

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(4+3x^3-7x^2)÷(2+3x)
(4+3x^3-7x^2)÷(2+3x)

(4+3x^3-7x^2)÷(2+3x)
(4+3x^3-7x^2)÷(2+3x)
=[3x²(x-1)-4(x-1)(x+1)]÷(2+3x)
=(x-1)(3x²-4x-4)÷(2+3x)
=(x-1)(3x+2)(x-2)/(2+3x)
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