已知a²+b²-4a-2b+5=0,求√a+√b/√2b-√a-b

已知a²+b²-4a-2b+5=0,求√a+√b/√2b-√a-b
已知a²+b²-4a-2b+5=0,求√a+√b/√2b-√a-b

已知a²+b²-4a-2b+5=0,求√a+√b/√2b-√a-b
a²+b²-4a-2b+5=0
（a²-4a+4）+(b²-2b+1)=0
(a-2)²+(b-1)²=0
a=2 b=1
√a+√b/√2b-√a-b
=(√2+√1)/(√2-√2-1)
=(√2+1)/(√2-1)
=(√2+1)²/（√2+1）（√2-1）
=（2+2√2+1）/（2-1）
=1.5+√2

+b²-4a-2b+5=0,求√a+√b/