作业帮2/[(2^x)+1]+2/[(2^-x)+1]答案是等于2但是我化来化去化不出啊!
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2/[(2^x)+1]+2/[(2^-x)+1]答案是等于2但是我化来化去化不出啊!
2/[(2^x)+1]+2/[(2^-x)+1]
答案是等于2
但是我化来化去化不出啊!
2/[(2^x)+1]+2/[(2^-x)+1]答案是等于2但是我化来化去化不出啊!
=[2*2^(-x)+2+2*2^x+2]/[2^x+1][2^(-x)+1]
=2[2^x+2^(-x)+2]/[1+2^x+2^(-x)+1]
=2[2^x+2^9-x)+2]/[2^x+2^(-x)+2]
=2
2/[(2^x)+1]+2/[(2^-x)+1] 后面的分数上下同乘2^x得
2/[(2^x)+1]+2x^2/[1+2^x] =(2+2x^2)/(1+2^x)=2
看不懂你写的@@
2/[(2^x)+1]+2/[(2^-x)+1]
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