3y+7/(y-1)(y-2)=A/(y-1)+B/(y-2),则A=( )B=( )若x+1/x=3,则x²/x^4+x²+1=( )

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3y+7/(y-1)(y-2)=A/(y-1)+B/(y-2),则A=( )B=( )若x+1/x=3,则x²/x^4+x²+1=( )
3y+7/(y-1)(y-2)=A/(y-1)+B/(y-2),则A=( )B=( )
若x+1/x=3,则x²/x^4+x²+1=( )

3y+7/(y-1)(y-2)=A/(y-1)+B/(y-2),则A=( )B=( )若x+1/x=3,则x²/x^4+x²+1=( )
(1)3y+7=A(y-2)+B(y-1)=(A+B)y-2A-B;所以A+B=3,-2A-B=7;解得A=-10,B=13;
(2)题是求x^2/(x^4+x^2+1)吗?