若(1-a/x^3)(2x-1/√x)^6的展开式中各项系数的和为0,则该展开式中常数项为多少

若a^2x=√2 -1,则(a^3x+a^-3x)/(a^x+a^-x)等于? a+x/x+1 ,x/x^2-2x-3 ,a/x^2+4x+3 若A={x|(1/2)^(x+2)(x-3)>1}B={x|(3a-x)/(x-a) *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式：X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X. x^2-6x+5= A(x-2)(x-3)B(x-6)(x+1) xy²/(x²y) - y×x²/(x²+x)=(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=2a/(a²-4) - 1/(a-2)=2/(1-a ) - 1/(a-1)=x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 x^2-x/x+1÷x/x+1 ；x^2+6x+9/x^2-9÷x+2/x-3；2/a÷4/a 若f(x)={a'x(x>1),(4-a/2)x+2(x 2x-3/x^2-x-A/x-1+B/x求A+B 计算:1/(a-x)-1/(a+x)-2x/(a^2+x^2)-4x^3/(a^4+x^4) 设f(x)=1/√(3-x)+lg(x-2),那么f(x+a)+f(x-a)(0 设f(x)=1/√(3-x)+lg(x-2),那么f(x+a)+f(x-a)(0 若3x+7/（x-1)(x-2)=A/x-1+B/x-2 则A= B= 若U=R,A={x|(1/2)^(x+2)(x -3)>1},B={x|log3(x-a) 若U=R,A={x|(1/2)^(x+ 2)(x- 3)>1},B={x|log3(x-a) 若U=R,A={x|(1/2)^(x+2)(x -3)>1},B={x|log3(x-a)