请问,x=(a+1)/(a-1),y=(2a-3)/(3a-2)用x表示y

请问,x=(a+1)/(a-1),y=(2a-3)/(3a-2)用x表示y
请问,x=(a+1)/(a-1),y=(2a-3)/(3a-2)用x表示y

请问,x=(a+1)/(a-1),y=(2a-3)/(3a-2)用x表示y
x=(a-1+2)/(a-1)=(a-1)/(a-1)+2/(a-1)=1+2/(a-1)
2/(a-1)=x-1
a-1=2/(x-1)
a=2/(x-1)+1=(x+1)/(x-1)
2a-3=2(x+1)/(x-1)-3=(2x+2-3x+3)/(x-1)=(-x+5)/(x-1)
3a-2=3(x+1)/(x-1)-2=(3x+3-2x+2)/(x-1)=(x+5)/(x-1)
所以y=([(-x+5)/(x-1)]/[(x+5)/(x-1)]=(-x+5)/(x+5)

由x=(a+1)/(a-1)得x(a-1)=a+1
得ax-x=a+1
得ax-a=x+1
得a=(x+1)/(x-1)
只要把a带入y那里
就可以了啊

因为x=(a+1)/(a-1)，所以a=(x+1)/(x-1)
把上式代入y=(2a-3)/(3a-2)，得y=(5-x)/(x+5)

x=(a+1)/(a-1),
(a-1)x=a+1
a=(x+1)/(x-1)
y=(2a-3)/(3a-2)
=[2(x+1)/(x-1)-3]/[3(x+1)/(x-1)-2]
=[(5-x)/(x-1)]/[(x+5)/(x-1)]
=(5-x)/(5+x)