1计算:(a+b)÷(a方+ab)= 2当m= 时,等式x-1分之x=(x-1)(1-m)分之x(m+2)成立.3已知y分之x=3,则x方-xy分之2xy= 4计算(x-y)÷(x方-2xy+y方) (25-x方)÷(x方-10x+25) 5已知a-b=0,求分式ab+b方分之x方-y
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/03 16:57:58
1计算:(a+b)÷(a方+ab)= 2当m= 时,等式x-1分之x=(x-1)(1-m)分之x(m+2)成立.3已知y分之x=3,则x方-xy分之2xy= 4计算(x-y)÷(x方-2xy+y方) (25-x方)÷(x方-10x+25) 5已知a-b=0,求分式ab+b方分之x方-y
1计算:(a+b)÷(a方+ab)= 2当m= 时,等式x-1分之x=(x-1)(1-m)分之x(m+2)成立.
3已知y分之x=3,则x方-xy分之2xy= 4计算(x-y)÷(x方-2xy+y方) (25-x方)÷(x方-10x+25) 5已知a-b=0,求分式ab+b方分之x方-y方
6已知x+y=2,x-y=1,求分式x方2xy+y方分之x方-y方的值。
7已知x分之1-y分之1=3,求分式x-2xy-y分之2x+3xy-2y的值。
8先化简分式x方-2x+1分之6x-6,再讨论:当整数x取何值时,能使分式的值是整数?
9已知ab分之a+b=6,bc分之b+c=8,ac分之a+c=10,其中a,b,c为任意实数。求分式abc分之ab+bc+ca的值。
1计算:(a+b)÷(a方+ab)= 2当m= 时,等式x-1分之x=(x-1)(1-m)分之x(m+2)成立.3已知y分之x=3,则x方-xy分之2xy= 4计算(x-y)÷(x方-2xy+y方) (25-x方)÷(x方-10x+25) 5已知a-b=0,求分式ab+b方分之x方-y
1计算:(a+b)÷(a方+ab)= 1/a
2当m= -1/2 时,等式x-1分之x=(x-1)(1-m)分之x(m+2)成立.
1-m=m+2
∴m=-1/2
3已知y分之x=3,则x方-xy分之2xy= 1
x/y=3
∴x=3y
∴x方-xy分之2xy=2y/(x-y)=2y/(3y-y)=1
4计算
(x-y)÷(x方-2xy+y方)
=(x-y)/(x-y)²
=1/(x-y)
(25-x方)÷(x方-10x+25)
=-(x+5)(x-5)/(x-5)²
=(x+5)/(5-x)
5已知a-b=0,求分式ab+b方分之x方-y方
这个题目似乎有点问题