已知x^2+√2y=√3,y^2+√2x=√3,且x≠y,求x+y的值

已知x^2+√2y=√3,y^2+√2x=√3,且x≠y,求x+y的值
已知x^2+√2y=√3,y^2+√2x=√3,且x≠y,求x+y的值

已知x^2+√2y=√3,y^2+√2x=√3,且x≠y,求x+y的值
x²+√2y=√3
y²+√2x=√3
x²-y²+√2(y-x)=0
(x+y)(x-y)-√2(x-y)=0
(x-y)(x+y-√2)=0
因为x不等于y
所以x+y=√2