已知(x-2)^2+|y-6|=0,求2(xy+x^2y)-[2xy^2-3(1-x^2y)]-2的值

已知(x-2)^2+|y-6|=0,求2(xy+x^2y)-[2xy^2-3(1-x^2y)]-2的值
已知(x-2)^2+|y-6|=0,求2(xy+x^2y)-[2xy^2-3(1-x^2y)]-2的值

已知(x-2)^2+|y-6|=0,求2(xy+x^2y)-[2xy^2-3(1-x^2y)]-2的值
解
(x-2)²+/y-6/=0
∴x-2=0,y-6=0
∴x=2,y=6
∴原式
=2xy+2x²y-2xy²+3(1-x²y)-2
=2xy+2x²y-2xy²+3-3x²y-2
=2xy-x²y-2xy²+1
=2×2×6-4×6-2×2×36+1
=24-24-144+1
=-143

(x-2)^2+|y-6|=0，则x=2，y=6
原式=2xy-2xy^2-yx^2+1=-143

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