1/n+1+1/n+2+1/n+3+...+1/2n>m/24n对于一切n∈n都成立,则正整数m的最大值为
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1/n+1+1/n+2+1/n+3+...+1/2n>m/24n对于一切n∈n都成立,则正整数m的最大值为
1/n+1+1/n+2+1/n+3+...+1/2n>m/24n对于一切n∈n都成立,则正整数m的最大值为
1/n+1+1/n+2+1/n+3+...+1/2n>m/24n对于一切n∈n都成立,则正整数m的最大值为
1/(n+1)+1/(n+2)+1/(n+3)+...+1/2n的每一项都>=1/2n,共有n个,
所以1/(n+1)+1/(n+2)+1/(n+3)+...+1/2n>n*1/2n=1/2,
令m/24n=1/2的m=12n,m的最大值为12n.
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