f(×)=sin2×+2(cos×+sin×)+3的值域怎么求?

f(×)=sin2×+2(cos×+sin×)+3的值域怎么求?
f(×)=sin2×+2(cos×+sin×)+3的值域怎么求?

f(×)=sin2×+2(cos×+sin×)+3的值域怎么求?
y=f(×)=sin2x+2(cos×+sin×)+3=2sinxcosx+2(cos×+sin×)+sin２x+cos２x+2=[sinx+cosx]２+2(cos×+sin×)+2 设m=sinx+cosx=根号2sin[x+45'] 则-根号2=