main(){int a=2,c=5;printf("a=%%d,b=%%d\n",a,这题没错,就是这样的,两个%,

void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { int x=3,y=5,*p=&x,*q=&y; fun(p,q);...void fun(int *a,int *b){ int *c; c=a;a=b;b=c;}main(){ int x=3,y=5,*p=&x,*q=&y; fun(p,q); printf(%d,%d,,*p,*q); fun(&x,&y); prin%d,%d ,*p,*q);}两 两个C语言的题 结果我有答案 但是和我算的不一样 1.main(){ int i=2,p;p=f(i,++i); printf(%d,p);}int f(int a,int b){ int c;if(a>b) c=1;else if(a==b) c=0;else c=-1;return(c);}2.main(){ int i=2,p;p=f(i,i++); printf(%d,p);}int f(int #include int a=3,b=5; max (int a,int b) {int c; c=a>b?a:b; return (c); } void main() {int main(){int a[ ]={ 2,5,3,6,8}; int *p,i=1,s=0; for ( p=a; p 131 以下程序运行后,输出结果是 A)84 B)99 C)95 D)44 int d=1; fun (int p) { int d=5; d+=p++; printf(int d=1;fun (int p) { int d=5; d+=p++; printf(%d,d); } main() { int a=3; fun(a); d+=a++; printf(%d ,d); } void fun(int p) { int d=2; p=d++; printf(%d,p); } main() { int a=1; fun(a); printf(%d ,a); } c语言定义指针问题 *p我能明白.main( ){ int a[5]={2,4,6,8,10},*p,**k;p=a;k=&p;printf(“%d,”,*(p++) );printf(“%d ”,**k);}还有**k的使用方法. #include stdio.h main() { int a []={1,2,3,4,5},*p;p=a;*(p+2)+=2; printf(%d,%d,*p,*(p+2));} #include void fun(int p) { int d=2; p=d++; printf(“%d”,p);} main() { int a=1; fun(a); printf(“%d #include main() {int a[10]={1,2,3,4,5,6},*p; p=a; *(p+3)+=2; printf(%d,%d,*p,*(p+3));求详解 让人费解的一道C语言题目#include int func(int a,int b);void main(){int k=4,m=1,p;p=func(k,m);printf(%d,,p);p=func(%d ,p);}int func(int a,int b){static int m=0,i=2;i+=m+1;m=i+a+b;return(m);}A.8,17 B.8,16 C.8,20 D.8,8能将下为什么 矩阵相加（C++）#include using namespace std; const int rows=3;const int cols=3;void matrixadd(int *,int *,int *,int,int);int main(){int a[rows][cols]={{1,3,5},{7,8,11},{13,15,17}};int b[rows][cols]={{9,8,7},{6,5,4},{3,2,1}};int c[rows][cols]={0 main() {int a[5]={2,4,6,8,10},*p,**k; p=a; k=&p; printf(%d,*(p++)); printf(%d ,**k); }为什么结果是24 void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { int x=3,y=5,*p=&x,*q=&y; fun(p,q);...void fun(int *a,int *b){int *c;c=a;a=b;b=c;}main(){int x=3,y=5,*p=&x,*q=&y;fun(p,q); printf(%d,%d,,*p,*q);fun(&x,&y); prin%d,%d ,*p,*q);}两次调用 求解定义函数那边有个c=a;是什么意思,有什么用,看不懂- - .#includeint f(int,int)main() {int i=2,p; p=f(i,i+1);printf(%d ,p)；｝int f(int a,int b){int c;c=a;if(a>b) c=1;else if(a==b) c=0;else c=-1;return (c);} void fun(int a,int b) { int t; t=a;a=b;b=t; } main()void fun(int a,int b){ int t; t=a;a=b;b=t; } main() { int c[10]={1,2,3,4,5,6,7,8,9,0}.i; for(i=0;i fun ( int *p ) { int a=10; p = &a; ++a; } main ( ) { int a=5; fun (&a); printf (%d ,a); }#include fun ( int *p ) { int a=10; p = &a; ++a; } main ( ) { int a=5; fun (&a); printf (%d ,a); } 37、有以下程序 int a=2; int f(int *a) {return (*a)++;} main( ) { int s=0; { int a=5; s+=f(&a); } s+答案为什么是C,37、有以下程序 int a=2; int f(int *a) {return (*a)++;} main( ) { int s=0; { int a=5; s+=f(&a); } s+=f(&a); printf(%d