若xy=1,则(x+y)^2-(x-y)^2的值是多少?
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若xy=1,则(x+y)^2-(x-y)^2的值是多少?
若xy=1,则(x+y)^2-(x-y)^2的值是多少?
若xy=1,则(x+y)^2-(x-y)^2的值是多少?
答:
xy=1
(x+y)^2-(x-y)^2 平方差公式
=(x+y+x-y)(x+y-x+y)
=2x(2y)
=4xy
=4
展开,可得4xy=4
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