[(x-y)的平方+(x+y)(x-y)]除以2x
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[(x-y)的平方+(x+y)(x-y)]除以2x
[(x-y)的平方+(x+y)(x-y)]除以2x
[(x-y)的平方+(x+y)(x-y)]除以2x
解
[(x-y)²+(x+y)(x-y)]÷2x
=[x²-2xy+y²+x²-y²]÷2x
=(2x²-2xy)÷2x
=x-y
=(x²-2xy+y²+x²-y²)÷2x
=(2x²-2xy)÷2x
=x-y
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