(x+1)(x-2)+(2x+1)(x-5)-3(x的平方-6x-1),其中x=1/4,先化简,再求值
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(x+1)(x-2)+(2x+1)(x-5)-3(x的平方-6x-1),其中x=1/4,先化简,再求值
(x+1)(x-2)+(2x+1)(x-5)-3(x的平方-6x-1),其中x=1/4,先化简,再求值
(x+1)(x-2)+(2x+1)(x-5)-3(x的平方-6x-1),其中x=1/4,先化简,再求值
原式=x²-x-2+2x²-9x-5-3x²+18x+3
=8x-4
=8×1/4-4
=-2
x-1)(x+2)+(2x-1)(x+5)-3(x的平方-6x-1)=x平方+x-2+2x平方+9x-5-3x平方+18x+3=28x-4=4(7x-1)x=7/2 28x=14*7=98所以28x-4=98-4=94
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