(1-x/3-x)^2÷(x^2-6x+9/9-x^2)*1/x^2-2x+1
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 01:57:18
(1-x/3-x)^2÷(x^2-6x+9/9-x^2)*1/x^2-2x+1
(1-x/3-x)^2÷(x^2-6x+9/9-x^2)*1/x^2-2x+1
(1-x/3-x)^2÷(x^2-6x+9/9-x^2)*1/x^2-2x+1
A={x|x^2-2x-3<3(1-x)}={x|x^2+x-6<0}={x|-3<x<2}
B={x|9-x^2>6-2x}={x|x^2-2x-3<0}={x|-1<x<3}
A∩B={x|-1<x<2}={x|x^2-x-2<0}
a+b=-3
改过了...但是你求的是a+b还是A+B?
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