1.[(x-y)^2-2(y -x)]÷(x-y)2.[(3a-7)^2-(a+5)^2]÷(4a-24)3.(1-16^4)÷(4x^2+1)÷(2x+1)4.(x+y)^3-2(x+y)^2+(x+y)5.a(x-y)-a^2(y-x)

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/06 03:47:33

1.[(x-y)^2-2(y -x)]÷(x-y)2.[(3a-7)^2-(a+5)^2]÷(4a-24)3.(1-16^4)÷(4x^2+1)÷(2x+1)4.(x+y)^3-2(x+y)^2+(x+y)5.a(x-y)-a^2(y-x)
1.[(x-y)^2-2(y -x)]÷(x-y)
2.[(3a-7)^2-(a+5)^2]÷(4a-24)
3.(1-16^4)÷(4x^2+1)÷(2x+1)
4.(x+y)^3-2(x+y)^2+(x+y)
5.a(x-y)-a^2(y-x)

1.[(x-y)^2-2(y -x)]÷(x-y)2.[(3a-7)^2-(a+5)^2]÷(4a-24)3.(1-16^4)÷(4x^2+1)÷(2x+1)4.(x+y)^3-2(x+y)^2+(x+y)5.a(x-y)-a^2(y-x)
1.[(x-y)^2-2(y -x)]÷(x-y)
=[(x-y)^2+2(x-y)]÷(x-y)
=(x-y)(x-y+2)÷(x-y)
=x-y+2
2.[(3a-7)^2-(a+5)^2]÷(4a-24)
=(3a-7+a+5)(3a-7-a-5)÷4(a-6)
=(4a-2)(2a-12)÷4(a-6)
=4(2a-1)(a-6)÷4(a-6)
=2a-1
3.(1-16^4)÷(4x^2+1)÷(2x+1)
我感觉有错
4.(x+y)^3-2(x+y)^2+(x+y)
=（x+y)[(x+y)^2-2(x+y)=1]
=(x+y)(x+y-1)^2
5.a(x-y)-a^2(y-x)
=a(x-y)+a^2(x-y)
=a(x-y)(1+a)

1.原式=(x-y)（x-y+2)/(x-y)=x-y+2
2.(3a-7+a+5)(3a-7-a-5)/4(a-6)=(4a-2)(2a-12)/4(a-6)=2a-1

1.(x-y+2)
2.(2a-1)
3.题打错了吧
4.(x+y)(x+y-1)
5.a(a+1)(x-y)

1.[(x-y)^2-2(y -x)]÷(x-y)
得：[(x-y)^2+2(x-y)]÷(x-y)=[(x-y)(x-y+2)]/(x-y)=x-y+2
2.[(3a-7)^2-(a+5)^2]÷(4a-24)
得：{[(3a-7)+(a+5)][(3a-7)-(a+5)]}/4(a-6)=[(4a-2)(2a-12)]/4(a-6)
...

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1.[(x-y)^2-2(y -x)]÷(x-y)
得：[(x-y)^2+2(x-y)]÷(x-y)=[(x-y)(x-y+2)]/(x-y)=x-y+2
2.[(3a-7)^2-(a+5)^2]÷(4a-24)
得：{[(3a-7)+(a+5)][(3a-7)-(a+5)]}/4(a-6)=[(4a-2)(2a-12)]/4(a-6)
=[2(2a-1)*2(a-6)]/4(a-6)
=2a-1
3.(1-16^4)÷(4x^2+1)÷(2x+1)
我认为这题你题目应该给错了吧？
4.(x+y)^3-2(x+y)^2+(x+y)
得：(x+y)[(x+y)^2-2(x+y)+1]=(x+y)(x+y-1)^2
5.a(x-y)-a^2(y-x)
得：a(x-y)+a^2(x-y)=（a+a^2)(x-y)=a(a+1)(x-y)

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