数列{an}满足:a1=1,an+1-sinθ^2*an=cos2θ*cosθ^2n,对于θ∈(0,∏/2),{an}前n项和为Sn,比较Sn+2与4/sin(2θ)^2对不起是,an+1-(sinθ)^2*an=cos2θ*(cosθ)^2n
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数列{an}满足:a1=1,an+1-sinθ^2*an=cos2θ*cosθ^2n,对于θ∈(0,∏/2),{an}前n项和为Sn,比较Sn+2与4/sin(2θ)^2对不起是,an+1-(sinθ)^2*an=cos2θ*(cosθ)^2n
数列{an}满足:a1=1,an+1-sinθ^2*an=cos2θ*cosθ^2n,对于θ∈(0,∏/2),{an}前n项和为Sn,比较Sn+2与4/sin(2θ)^2
对不起是,an+1-(sinθ)^2*an=cos2θ*(cosθ)^2n
数列{an}满足:a1=1,an+1-sinθ^2*an=cos2θ*cosθ^2n,对于θ∈(0,∏/2),{an}前n项和为Sn,比较Sn+2与4/sin(2θ)^2对不起是,an+1-(sinθ)^2*an=cos2θ*(cosθ)^2n
建议你把括号标注明白一些:cosθ^2n是cosθ的2n次方,还是cos(θ^2n),还是cosθ…^2 *
完全不理解...
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