x→π/2lim(1+2cosx)1/cos次方用第二个重要公式求出极限

求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0 lim(x→0)(cosx)^(1/ln(1+x^2)) lim(x->0)[cosx^(1/2)]^(π/x) limx→0(cosx)^(1/x^2)求解lim(x→0)((cosx)^(1/x^2)) lim(x→0)[(secx)^2-1] /(1-cosx) lim x→0(1+2cosx)^secx lim(x→π/3)sin(x-π/3)/(1-2cosx) lim(x→π/3)sin(x-π/3)/(1-2cosx)= 初学者 求下列极限 lim（x→0）(1-cosx*√cosx*cosx的立方根)/x^2 求极限lim x→π/2(1+cosx)secx secx是(1+cosx)的上标 已知lim(x→0) f(x)/(1-cosx) =2 求lim(x→0) [1+f(x)]^½ 求Lim(x→0)(sinx/x)^(cosx/1-cosx) lim(x趋向0+)x/[(1-cosx)^(1/2)] lim x->0 cos(2x)-1 / cosx -1 = (1) lim(x->正无穷) x-lnx (2) lim(x->0+) cosx^1/x^2 lim（x趋向于0）（1-cosx)/x^2 x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)是怎么通分的?x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)thank you lim x→π/2 {（根号2）+cosx/2}/（1+sinx） 函数的极限