设f(xy,x-y)=x²+y²,则f(x,y)=?设f(x-y,x+y)=xy,求f(x,y) 这两道题是同一种题型 教教呀

设f(xy,x-y)=x²+y²,则f(x,y)=?设f(x-y,x+y)=xy,求f(x,y) 这两道题是同一种题型 教教呀
设f(xy,x-y)=x²+y²,则f(x,y)=?
设f(x-y,x+y)=xy,求f(x,y) 这两道题是同一种题型 教教呀

设f(xy,x-y)=x²+y²,则f(x,y)=?设f(x-y,x+y)=xy,求f(x,y) 这两道题是同一种题型 教教呀
f(xy,x-y)=x²+y²=-2xy+(x-y)^2
因此f(x,y)=-2x+y^2
f(x-y,x+y)=xy=1/4[(x+y)+(x-y)][(x+y)-(x-y)]
f(x,y)=1/4(y+x)(y-x)=1/4(y^2-x^2)